In an L-C-R circuit with all components connected in series,the e.m.f. and the current flowing in the circuit are given by the following equation : `e_d = 200 sin (314 .t + pi//6)` Volt,I = 5 sin 314 t A. obtain: The phase difference between current and e.m.f.

In an L-C-R circuit with all components connected in series,the e.m.f. and the current flowing in the circuit are given by the following equation : e_d = 200 sin (314 .t + pi//6) Volt,I = 5 sin 314 t A. obtain:The peak values of current and e.m.f.

In an L-C-R circuit with all components connected in series,the e.m.f. and the current flowing in the circuit are given by the following equation : e_d = 200 sin (314 .t + pi//6) Volt,I = 5 sin 314 t A. obtain: The frequency of the a.c. source.

The e.m.f of and a.c. current E=158sin 200pit V . What is the voltage at time t=1/400 sec?

A series combination of an inductor of self-inductance L, capacitor of capacitance C and resistor R is connected to an alternating voltage source of V=V_0sinomegat . The current through the circuit is I=I_0sin(omegat-theta) ,where I_0=V_0/(sqrt(R^2+(omega-1/(omegaC))^2)) and theta=tan^-1 ""1/R(omegaL-1/(omegaC)) . Now that, the frequency of both voltage and current is f=omega/(2pi) . The rms value of these parameters during one complete cycles are V_(rms)=V_0/sqrt2 and I_(rms)=I_0/sqrt2 respectively. These values are shown in alternating voltmeter and ammeter. The power consumed by the circuit P=VI. The mean value i.e., the effective power of the circuit in a complete cycle is overlineP=V_(rms)I_(rms)costheta . This costheta is termed the power factor. In the circuit in question (i) the inductor is replaced by a pure capacitor, the phase difference between the current and terminal voltage of the capacitor is

An emf of V= V_0sin omegat is applied on a series LCR circuit. IF there is no phase difference between the voltage and current then,

In an LCR series combination, R=400 Omega L=100mH and C=1muF . This combination is connected to a 25sin2000t volt source. Find phase difference of voltage and current

An alternating emf of E=20sin 1000tV is applied on a circuit containing a pure resistance of 25Omega in series with a coil of self-inductance 40 mH and resistance 15Omega . Find out the phase difference between E and the current I.

An electric bulb is connected to battery of e.m.f. 10V and 0.01 A current is flowing through the bulb. But when it is connected to 220V mains then the cureent is 0.05 A. Explain this apparent discrepancy with ohm's law.

In an ac circuit alternating voltage E= 200sqrt2 sin 100t volt is connected to a capacitor of capacity 1muF . The rms value of the current in the circuit is

AC voltage is applied on purely inductive circuit of inductance L. If the voltage be e= E_0sin (omegat) then show mathematically current lags behind the voltage by a phase difference pi/2