In a potentiometer experiment the null point is obtained at 5.20 m for a cell. A Shunt resistance of `5 Omega` is added. The new null point is at 4:00 m. What is the internal resistance of the cell ?

In a potentiometric arrangement ,a cell is connected to the potentiometer wire of 60 cm in length to make the deflection zero in galvanometer . Now if the cell is shunted with a 6Omega resistor , a null point is found in 50 cm length of the wire . What is the internal resistance of the cell ?

In a potentimeter experiment , it is found that no current passes through the galvanometer when the termials of the cell are connected across 52 cm of the potentimeter wire . If the cell is shunted by a resistance of 5Omega , a balance is found when the cell is connected across 40 cm of the wire . Find the internal resistance of ht cell .

In a metre-bridge [Fig.], the null point is found to be at a distance of 33.7 cm from A. If now a resistance of 12Omega is connected in parallel with S, the null point occurs at 51.9 cm. Determine the resistance of R and S.

In a potentiometer experiment . A cell produces balance in the wire at 240 cm. balancing length change to 120 cm when a resistance 2Omega Is connected parallel to the cell. Find out the internal resistance of the cell.

When a resistance of 12 Omega is conencted with a cell of emf 1.5 V,0.1 A current flows through the resistance internal resistance of the cell is

When a resistance of 12 Omega is connected with a cell of emf 1.5 V, 0.1A current flows through the resistance. Internal resistance of the cell is—

The electromotive force of a cell is 2V. The potential difference becomes 1.5 V when a resistance of 15 Omega is added to the two ends of the cell. Determine the internal resistance of the cell and the lost volt.

A wire of resistance 5 Omega is stretched 20%. IF the volume remains constant , find the new resistance.

In a metre bridge experiment , a null point is obtained at a length of 39.8 cm when a 2Omega resistance is placed in the left gap and a 3Omega resistance in the right gap . If the two resistance are interchanged , the null point is obtained at 60.8 cm . Calculated the end errors of the bridge .

A length of potentiometer wire of 155 cm balances the emf of a cell in a circuit and a length of 135 cm when the cell has a conductor of resistance 8Omega connected between its terminals . Find the internal resistance of the cell .