A resistance `1000 Omega` is connected to a `100 V` supply line. A voltmeter is connected across one end and the mid-point of the resistance and reads 40 V. Find the resistance of voltmeter.

With a uniform potentimeter wire AB of resistance 100Omega , an electric cell of negligible internal resistance and a voltmeter 360 Omega is connected in between A and the mid -point C of the wire . If the reading of the voltmeter be 1.0 V , determine the emf of the cell .

In a supply line of 100 V there is a resistance of 1000 Omega . In between our terminal of the resistance and its mid point, a voltmeter is connected which gives a reading of 40 V. determine the resistance of the voltmeter.

A battery of emf 1.4V and interna! resistance 2Omega is connected to a resistor of 100Omega resistance through an ammeter. The resistance of ammeter is 4/3Omega a voltmeter has also been connected to find the potential difference across the resistor. The ammeter reads 0.02 A. What is the resistance of voltmeter.

A cell of emf 3.4V and internal resistance 3Omega is connected to an ammeter having resistance 2Omega . and to an external resistance of 100Omega . When a voltmeter is connected across the 100Omega resistance the ammeter reading is 0.04A. Find the voltage read by the voltmeter and its resistance. Had the voltmeter been an ideal one what would have been its reading ?

When an exteranal resistance is connected to a battery of emf 80 V , an ammeter records 200 mA . If A voltmeter is connected to the two ends os the external resistance ,it records 60 V . Determine the rate of supply of energy by theresistance .

When a voltmeter of resistance 100 Omega is connected with an electric cell, the reading of the voltmeter is 2V. When the cell is connected with a resistance of 15 Omega . An ammeter of resistance 1 Omega given the reading of 0.1 A.Determine the emf of the cell.

A galvanometer (coil resistance 99Omega ) is converted into an ammeter using a shunt of 1Omega and connected as shown in figure (a). The ammeter reads 3A. The same galvanometer is converted into a voltmeter by connecting a resistance of 101Omega series. This voltmeter is connected as shown in figure (b). Its reading if found to be 4/5 of the full scale reading. Find internal resistance r of the cell.

A 220 V - 60 W electric lamp os connected to 220 V supply line . Determine the resistance of the lamp in incandescent state .

A cell of emf 1.4V and internal resistance 2 Omega is connected in series with a resistance of 100 Omega and an ammeter. The resistance of the ammeter is 4/3 Omega .To measure the potential difference between the two ends of the resistance a voltmeter is connected IF the reading of the ammter is 0.02 A.what is the resistance of the voltmeter?

Two resistor of magnitudes 300 Omega and 400 Omega are connected with a source of 60 V emf in series. A voltmeter connected across 400 Omega reads 30V.What will be the voltmeter reading when it is connected across 300 Omega .