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Prove that current density of a metallic...

Prove that current density of a metallic conductor is directly proportional to the drift speed of electrons.

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If a current passes through a metal conducting wire of area of cross section A, the drift velocity of free electrons inside the metal is v_d=1/( n e A) , where the amount of electric charge of an electron =e and the number of free electrons per unit volume of the metal=n. The applied electric field on the wire is E=V/l , where a potential difference V exists between two points, l apart, along the length of the wire. IF R is the resistance of the wire between those two points, then the resistivity of its material is rho=(RA)/l .Besides the mobility (mu) of the free electrons inside a wire is defined as their drift velocity for a unit applied electric field. The radii of two wires ,made of two different metals are in the ratio 1:2 , The number density of free electrons in the first metal is double that in the second metal. IF the current in the first wire is 1A, then the current in the second wire producing the same drift velocity is

If a current passes through a metal conducting wire of area of cross section A, the drift velocity of free electrons inside the metal is v_d=1/( n e A) , where the amount of electric charge of an electron =e and the number of free electrons per unit volume of the metal=n. The applied electric field on the wire is E=V/l , where a potential difference V exists between two points, l apart, along the length of the wire. IF R is the resistance of the wire between those two points, then the resistivity of its material is rho=(RA)/l .Besides the mobility (mu) of the free electrons inside a wire is defined as their drift velocity for a unit applied electric field. The current through unit cross section of a conductor,called the electric current density J, is related with the applied electric field E as

If a current passes through a metal conducting wire of area of cross section A, the drift velocity of free electrons inside the metal is v_d=1/( n e A) , where the amount of electric charge of an electron =e and the number of free electrons per unit volume of the metal=n. The applied electric field on the wire is E=V/l , where a potential difference V exists between two points, l apart, along the length of the wire. IF R is the resistance of the wire between those two points, then the resistivity of its material is rho=(RA)/l .Besides the mobility (mu) of the free electrons inside a wire is defined as their drift velocity for a unit applied electric field. Two copper wires have both lengths and radii in the ratio 1:2 if the ratio between the electric currents flowing through them is also 1:2 , what would be the ratio between the drift velocities of free electrons?

UNITED BOOK HOUSE-MODEL PAPER SET-08-EXERCISE
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  5. What is a photodiode? Draw theI-V characteristic curve of a photodiode...

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  6. Prove that current density of a metallic conductor is directly proport...

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  7. Define mobility of free electrons.

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  8. The potential difference between the terminals of a cell, in an open c...

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  9. State and explain Kirchhoff's laws for electrical circuits.

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  10. What is the principle of potentiomenter?

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  11. A potentiometer wire has a length 10m and a resistance of 4 ohm. A cel...

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  12. Define SI unit of magnetic flux.

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  13. Show that (dphi)/(dt) and V have the same dimension.

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  18. A resistance of 400Omega and a capacitance of reactance 200Omega are c...

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