A potentiometer wire has a length 10m and a resistance of 4 ohm. A cell of emf 2V and a resistance box are connected in series with it. Calculate the resistance to be introduced in the box, so as to get a potential gradient of `0.1Vm^-1`.

The resistance of a potentiometer wire of length 10m is 20 ohm. A resistance box and a 2 volt accumulator are connected series with it. Resistance required to be introduced in the box to have a potential drop of one microvolt per millimeter of the potentiometer wire will be

A potentiometer wire has length 4m and resistance 8Omega the resistance that must be connected in series with the wire and an accumulaterof emf 2 V so as to get a potential gradient 1 mV ,per cm on the wire is

A cell of emf 2Vand internal resistance 1.5Omega is connected to two ends of 100 cm wire. The resistance of the wire is 0.005 Omega//cm. The potential gradient of the wire is

Two cells , one of emf 1.2 V and internal resistance 0.5Omega the other of emf 2 V and internal resiatnce 0.1Omega are connnected in series with an external resistance of 5Omega . What is the current through this resistor ?

A potentiometer wire of length 100 cm has a resistance of 10Omega . It is connected in series with a resistance and a cell of emf 2V and of negligible internal resistance. A source of emf 10 mV is balanced against a length of 40 cm of the potentiometer wire. What is the value of external resistance ?

A potentiometer has 10 wires each of 1 meter length and the total resistance is 20Omega . Find the resistance to be connected to the driving battery of emf 2 volts to produce a potential drop of 1 mu V per millimeter.