In a circuit with resistance R, current is supplied with n identical cells. At what value internal resistance of each cell will the current through R be the same whether they are connected in series or in parallel?

Consider the circuit shown. If all the cells have negligible internal resistance. what will be the current through the 2 Omega resistor when steady state is reached ?

A certain circuit with resistance R- 100 Omega is powered by a direct current source. An ammeter with an internal resistance 1 Omega is connected to the circuit to measure the current .What was the current in the circuit before the ammeter was connected if the ammeter shows 5A?

In the given circuit the current in each resistance is

An electric cell is sending electric currents through a resistance of 10 Omega . IF a shunt of 1 Omega is connected with that resistance then the current through the 10 Omega resistance becomes half of the previous value.What is the resistance of the cell?IF the current through the shunt be 0.9A, then what will be the emf of the cell?

5 electric cells are connected in series .Emf of each cell is 1.5 V and internal resistance is 0.1 Omega .When this combination of cells is connected with an external circuit of resistance 4 Omega, what will be the current through that resistance? What resistance should be connected instead of 4 Omega so that the current will be halved?

n electric cells of emf e and internal resistance r each are connected in series.What is the emf of this combination.

The resistances of a galvanometer is 200 Omega and full-scale deflection is obtained for a current of 5mA. The galvanometer is connected with a source of electricity through a resistance of 58 Omega in series. The emf of the cell is 30V and its internal resistance is negligibly small .Find out the resistance of the shunt that should be connected with the galvanometer in parallel.

n electric cells having emf e and internal resistance r each are connected in parallel.What is the emf of this combination?