The resistance of a wire is `5Omega`. It is streached to increase length by 20%. If the volume is unaltered, then what is the final resistance.

A wire has resistance 5Omega . If it is stretched to increase the Length by 10% then what will be its final resistance?

A metallic wire is stretched to increase its length by 20% .What will be the percentage change of its resistance?

A wire of resistance 5 Omega is stretched 20%. IF the volume remains constant , find the new resistance.

A metallic wire has a definite resistance . IF the wire is stretched in such a way that its length becomes doubled then what will be the resistance of the wire? Consider the volume and the resistivity of the wire remains unchanged.

The resistivity of a wire if its length be doubled-

A metal write of resistance 6 ohm is stretched so that is length becomes double of its original length. What would be the final resistance?

A wire of resistance R is stretched till its length becomes n times its original length. What will be its new resistance?

The internal resistance of a battery of 100 V is 5 Omega . When the emf of the battery is measured by a voltmeter 20% error is found. What is the resistance of the voltmeter?

A potentiometer wire of length 100 cm has a resistance of 10Omega . It is connected in series with a resistance and a cell of emf 2V and of negligible internal resistance. A source of emf 10 mV is balanced against a length of 40 cm of the potentiometer wire. What is the value of external resistance ?