Show that the energy of `(He_2^4)` for first excited state is numerically equal to the ground state energy of Hydrogen atom..

Show that the energy of first excited state of He^(+) atom is equal to the energy of electron in the first orbit of hydrogen atom.

The total energy of an electron in the ground state , of hydrogen atom is

The hydrogen like species Li^(2+) is in a spherically symmetric state S_(1) with one radial node. Upon absorbing light, the ion undergoes transition to a state S_(2) . The state S_(2) has one radial node and its energy is equal to the ground state energy of the hydrogen atom. Q. Energy of the state S_(1) in units of the hydrogen atom ground state energy is-

The hydrogen like species Li^(2+) is in a psherically symmetric state S_(1) with one radial node. Upon absorbing light, the ion undergoes transition to a state S_(2) . The state S_(2) has one radial node and its energy is equal to the ground state energy of the hydrogen atom. Q. Orbital angular quantum number of the state S_(2) is-

The hydrogen like species Li^(2+) is in a psherically symmetric state S_(1) with one radial node. Upon absorbing light, the ion undergoes transition to a state S_(2) . The state S_(2) has one radial node and its energy is equal to the ground state energy of the hydrogen atom. Q. The state S_(1) is-

The ionisation energy of hydrogen is 13.6 eV. The energy of the photon released when an electron jumps from the first excited state (n=2) to the ground state of a hydrogen atom is

Total energy of an electron in a ground state of hydrogen atom will be—

The radius of the orbit of an electron in the ground state of hydrogen atom is a_0 . Then

Energy in the second energy state of hydrogen atom is E_2 . Then

Find out the wavelength of the electron orbiting in the ground state of hydrogen atom.