The threshold wave length for any metal is 400 nm. If 200 nm of U.V. light is incident on -the object? then what will be the maximum kinetic energy if the electrons `[h - 6.63xx10^-34J.S]`

For photoelectric emission, threshold wavelength of a metal is 2460 Å . If ultraviolet light of wavelength 1810 Å be incident on the metal, what will be the maximum kinetic energy of the emitted electrons? [Planck's constant = 6.62xx10^(-34) J.s , velocity of light in veccuum = 3xx10^(8) m.s^(-1) ]

For any metal the photoelectric threshold wavelength is 3800overset@A . An ultraviolet wave of wavelength 2000overset@A is incident on the metal then what will be- the maxinum kinetic energy of the photoelectrons. [given— h = 6.62 xx 10^(-34)J.S]

Threshold wavelength for photoelectric emission from a metal surface is 3800Å , Utraviolet light of wave-length 2600Å is incident on the metal surface. maximum kinetic energy of emitted photoelectron. (h = 6.63 xx 10^(-27) " erg.s")

Threshold frequency of a metal is 5xx10^(13)s^(-1) upon which 1xx10^(14)s^(-1) frequency light is focused. Then the maximum kinetic energy of emitted electron is-

A photon of energy 8eV is incident on a metal plate with threshold frequency 1.6 xx 10^(15) Hz. The maximum kinetic energy of the emitted photo electrons is (given h= 6 xx 10^(-34) Js )

Write down Einstein's photoelectric equation and mention the symbols used. The photoelectric threshold wavelength for a certain metal is 400 nm. Find the maximum kinetic energy of the emitted electrons from the metal surface by ultraviolet light of wavelength 200 nm. Given, h= 6.63 xx 10^(-34) J.s

Write down Einstein's photoelectric equation and mention the symbols used. The photoelectric threshold wavelength for a certain metal as 400mm. Find the maximum kinetic enrgy of the emitted electrons from the metal surface by ultraviolet light of wavelength 200nm. Given h=6.63xx10^34

Photoelectric threshold wavelength for a metal is 3800 Å . Find the maximum kinetic energy of emitted photoelectron, when ultraviolet radiation of wave length 2000Å is incident on the metal surface. Planck's constant, h = 6.62 xx 10^(-34) J.s

Work function of a metal is 2.3eV and on 1.0 cm^(2) area of that metal, a light of intensity 8.6 xx 10^(3) W.m^(-2) is incident. That intensity is distributed equally among the wavelength 4144 Å, 4972 Å and 6216 Å . If no ray is lost due to scattering and if each of the photons of proper energy can emit photoelectrons, what will be the number of photoelectrons emitted in 2 s? (h = 6.63 xx 10^(-34) J.s, 1eV = 1.6 xx 10^(-19)J)