The position vector of a particle `vecr =(t^2-1)hati +2thatj` . Determine the trajectory of the particle in the xy plane.

Position vector of a particle is related to time t as vecr=(t^2-1)hati+2thatj . The locus of the particle on the x-y plane is

The position vector of a particle is, vecr=3thati-2t^2hatj+4hatk . Find out (i) its velocity vecv and acceleration veca ,

The position vector of a particle is, vecr=3thati-2t^2hatj+4hatk . Find out (ii) the magnitude and direction of its velocity at t=2s.

A particle moves from a points vecr_1=hati+2hatj in metre to another point vecr_2=2hati+4hatj in metre under the action of a force vecF=2hati+3hatj in newton. Find the work done by the force on the particle in the displacement.

The position time relation of a moving particle is x = 2t - 3t^2 What is the maximum (+) ve velocity of the particle?

A particle under the influence of vecF=3hati + 5hatj in newton, moves from a point vecr_1 =hati+3hatj to vecr_2=2hati+4hatj . Find the work done by the force on the particle during the displacement.

The position-time relation of a moving particle is x = 2t -3t^(2) . When does the velocity of the particle become zero? (x is in metre and t is in second)

The position time relation of a moving particle is x = 2t - 3t^2 When does the velocity of the particle become zero? (x is in metre and t is in second)