Two springs having force constant `k_1 and k_2 (k_1 > k_2)` respectively increases its length by same amount. On which spring work done will be more aiid why?

Two spting having force constant k_1 and k_2 (k_1gt k_2) respectively increases its length by same amount . On which spring work done will be more and why?

Two springs have force constants K_1 and K_2 (K_1 gt K_2) . on application of same force which spring will perform more work?

Two springs have force constants K_1 and K_2 (K_1 gt K_2) . on which spring more work to be done to increase the length of the spring by same amount.

Force constant of two springs are k_1 and k_2(k_1 gt k_2) (i) The springs are elongated by the same amount and (ii) the springs are elongated by applying the same force. Then for which of the springs is more work performed?

An elastic spring of length L and of force constant k is stretched to increase its length by an amount x. The spring is further stretched to elongate it by y. The amount of work done in stretching the spring in the second case ( x and y are very small) is

Two springs P and Q of force constant k_p and k_q ( k_Q=k_P/2 ) are stretched by applying forces of equal magnitude. IF the energy stored in Q is E, then the energy stored in P is

Two massless springs of force constant K_(1) and K_(2) are joined end to end. The resultant force constant K of the system is

Force constant of two springs are K_1 and K_2 . If they are joined end to end then the force constant of the combination will be