In the s-t graph of a particle with uniform acceleration at time t makes an angle `45^@` with the time axis. After one second it makes angle of`60^@`. What is the acceleration of the particle?

s-t graph for a partical, moving with a constant acceleration, subtends 45^(@) angIe with the time axis at time t. That angle becomes 60^(@) 1s Iater. Find the acceleration of the partical.

If position of a particle at instant t is given by x = t^(4) find acceleration of the particle.

A particle moves with uniform acceleration and the distance travelled in t - th second is s_(t) = 3 + 2t . Find the initial velocity of the particle .

The displacement time graph for two particles A and B are straight lines inclined at angles 30^@ and 60^@ with the time axis,f he ratio of the velocities VA and VB is

The initial velocity of a particle- is u and acceleration (f) is uniform. Final velocity and distance covered in the interval t are v and s respectively. Show that the velocity of the particle at half - distance is more than the velocity for half-time.

The equation x= A sin omega t gives the relation between the time t and the corresponding displacement x of a moving particle where A and omega are constant. Prove that the acceleration of the particle is proportional to its displacement and is directed opposite to it.