The value of the acceleration due to gravity at a height h from the surface of the earth is `g_1`and that at a depth h below the earth’s surface is `g_2`. Show that `g_2/g_1`=`(1+h/R) `(Radius of earth R >> h) I.

The value of the acceleration due to gravity at a height h from the surface of the earth is g_1 and that at a depth h below the earth's surface is g_2 .Show that (g_2)/(g_1)=(1+h/R) [Radius of earth Rgt gt h ]

What is the value of the acceleration due to gravity on the surface of the earth ?

The acceleration due to gravity at a height R ( radius of the earth ) from the earth' s surface is

Assume that the earth is a uniform sphere of radius R. If the acceleration due to gravity at a height h above the earth's surface is g_1 and at the same depth below the surface of the earth is g_2(h lt R) , then show that, g_2=g_1(1-h/R)(1+h/R)^2 .

The acceleration due to gravity at a height above the earth's surface is ……..than that at the same depth below the surface of the earth. [Fill in the blanks]

Discuss the variation of g (ii) with depth below the earth's surface.

Draw the graph of variation of acceleraton due to gravity with the depth and height from the surface of the earth, assuming that the density of earth is costant.

Calculate the height from earth’s surface at which value of g is 1% than that of the earth surface.

Considering the earth as a uniform sphere of radius R show that if the acceleration due to gravity at a height h from the surface of earth is equal to the acceleration due to gravity at the same depth, then h=1/2(sqrt(5)-1)R.