The mean free path of oxygen gas molecules at STP is `9.5 times 10^-6 cm` What is the time interval between two successive collisions of a molecule? Atomic weight of oxygen=32 and `R=8.3 times 10^7 erg.mol^-1.K^-1`

The mean free path of oxygen molecule at NTP is 9.5 times 10^-6 cm What will be the time between two consecutive collisions of an oxygen molecule?( R=8.3 times 10^7 erg.mol^-1.K^-1 )

The mean free path for the collision of nitrogen molecules at STP is 6.44 times 10^-6 cm . What is the mean time interval between collisions? Given, R=8.31 times 10^7 erg.mol^-1.K^-1 , molecular mass of nitrogen=28.

Calculate the mean free path for the collision of nitrogen molecules at 0^@C temperature at 1 standard atmosphere pressure. The mean time interval between two successive collisions = 1.9 times 10^-10 s, R=8.31 times 10^7 erg.mol^-1.K^-1 molecular mass of nitrogen =28.

IF the rms speed of oxygen at STP is 4.6 times 10^4 cm.s^-1 What will be its density at STP?

Calculate the molecular kinetic energy of 1 g helium gas at 127^@C Molecular weight of helium=4 and R=8.3 times 10^7 erg. Mol^-1.K^-1 .

The rms speed of oxygen gas molecules at STP is 4.5 times 10^4 cm.s^-1 . Find out the same for carbon dioxide gas molecules at STP. Given the molecular weights of oxygen and carbon dioxide are 32 and 44, respectively.

Find out the kinetic energy of 2g of nitrogen gas at 27^@C . Given R=8.3 times 10^7 erg.mol^-1 K^-1 .

Resistivity of copper is 1.76 times 10^-6 Omega cm. What will be the resistance between two opposite faces of a copper cube of side 1 m?

Determine the rms speed of gas molecules at 27^@C [ R=8.3 times 10^7 erg.mol^-1.K^-1 , atomic weight of oxygen=16].

Determine the average energy of a gas molecule at 3940 K. R=8.31 times 10^7 erg.mol^-1.K^-1 and N=6.025 times 10^23 .