A body is moving from rest with an acceleration `a` `m`.`s^(-2)` which is related to time t s by `a = (3t +4)`. What will be its velocity in time 2 s?

The acceleration of an obeject starting from rest is related to time as a = Kt+c. What will be its velocity after time t ?

A particle is moving with uniform acceleration.its displacement at any instant t is given by S= 10t+4.9t^2 . What is its Initial velocity

A lift of height 3.375 m is moving up with an acceleration of 2.2 "m.s"^(-2) . What is the time required by any object to fall from the roof of the lift to its floor?

The relation between displacement & time of a body is S = (2t^3- 4t^2 + 3t) unit What will be the acceleration after 3s?

A body starts from rest and moves with an acceleration proportionaI to time. (i) Find its velocity n s after starting. (ii) What distance will it traveI in n s?

A car starting with velocity 10 "m.s"^(-1) attains an acceleration 1 "m.s"^(-2) . After what time interval will its velocity be 20 "m.s"^(-1) ?

A body of mass m , starting from rest , moves with constant acceleration . After a time T it attains a velocity V. Show that the work done by the body in time t=1/2 m (V^2)/(T^2)*t^2*

A train attains a velocity v after starting from rest with a uniform acceleration alpha . Then the train travels for sometime withuniform velocity, and at last comes to rest with a uniform retardation beta . If the overall displacement is s in time t , show that t = (s)/(v)+(v)/(2)((1)/alpha+(1)/(beta))

A particle moves with uniform acceleration and the distance travelled in t - th second is s_(t) = 3 + 2t . Find the initial velocity of the particle .