A drop of oil rises through water with an acceleration `alphag`. If `alpha` is a constant quantity and g is the acceleration due to gravity, find the specific gravity of the oil. Neglect the friction of water.

A drop of oil rises within water with an upward acceleration of alphag . If alpha is a constant and g is the acceleration due to gravity, find the specific gravity of the oil. Neglect the friction of water.

If G is universal gravitational constant and g is acceleration due to gravity then the unit of the quantity G/g is

State whether True or False : G is called acceleration due to gravity.

A planet has same density and same acceleration due to gravity as of earth and universal gravitational constant G is twice of earth. The ratio of their radii is

A hemi-spherical tank of radius 2 m is initially full of water and has an outlet of 12c m^2 cross-sectional area at the bottom. The outlet is opened at some instant. The flow through the outlet is according to the law v(t)=0.6sqrt(2gh(t)), where v(t) and h(t) are, respectively, the velocity of the flow through the outlet and the height of water level above the outlet and the height of water level above the outlet at time t , and g is the acceleration due to gravity. Find the time it takes to empty the tank.

A man of weight w is in a lift which is moving up with an acceleration a.If acceleration due to gravity is g, apparent weight of the man will be

Mass remaining constant , if the radius of the earth decreases by 1% what is the percentage change in acceleration due to gravity on the surface of the earth ?

Mass remaining constant, if the radius of the earth decreases by 1% what is the percentage change in acceleration due to gravity on the surface of the earth?