Home
Class 11
PHYSICS
The distance-time graph of a moving part...

The distance-time graph of a moving particle is given by `x = 4t -6t^(2)`. At what time would the speed of the particle be zero ? (`x` is in metre and `t` is in second).

Promotional Banner

Similar Questions

Explore conceptually related problems

The distance-time graph of a moving particle is given by x = 4t -6t^(2) . What is the positive maximum speed?

The position-time relation of a moving particle is x = 2t -3t^(2) . When does the velocity of the particle become zero? (x is in metre and t is in second)

The position-time relation of a moving, particle is x = 2t - 3t^2 :- When does the velocity of the particle become zero? (x is in metre and t is in second)

The position time relation of a moving particle is x = 2t - 3t^2 When does the velocity of the particle become zero? (x is in metre and t is in second)

The position-time relation of a moving particle is x = 2t -3t^(2) . What is the maximum positive velocity of the particle?

The position-time relation of a moving, particle is x = 2t - 3t^2 :- What is the maximum (+) ve velocity of the particle?

The position time relation of a moving particle is x = 2t - 3t^2 What is the maximum (+) ve velocity of the particle?

If the distance from the initial point at a time t is given by x = t - 6t^2 + t^3 : then at what time the acceleration will be zero?

If position of a particle at instant t is given by x = t^(4) find acceleration of the particle.

The distance covered by a particle in t seconds is given by x=3+8t-4t^(2) . After 1 second its velocity will be