A simple pendulum has a time period `T_1` when on earth's surface.and `T_2` when taken to a height R above the earth’s surface, where R is the radius of the earth. Find the ratio `T_2//T_1`.

Time period of a simple pendulum on the surface of the earth is T_(1) and at a hight R above the surface of the earth is T_(2) , here R is the radius of the earth. The ratio T_(2)//T_(1) is

The change in the gravitational potential energy when a body of mass m is raised to a height nR above the surface of the earth is (here R is the radius of the earth)

Calculate the height from earth’s surface at which value of g is 1% than that of the earth surface.

The height vertically above the earth's surface at which the acceleration due to gravity becomes 1% of its value at the surface is (R is the radius of the earth)

What is the condition for setting up an artificial satellite at a height h from the earth’s surface? (Radius of the earth = R, mass of the earth= M).

Two satellites A and B of the same mass revolve around the earth in circular orbits. They are at heights of R and 3R respectively from the surface of the earth (R=radius of the earth). Find the ratio of their kinetic energies and potential energies.