The time period of a particle executing S.H.M. is T sec. Find the time taken by the particle to reach maximum displacement in one side from equilibrium position.

What is the maximum displacement of a vibrating particle from the equilibrium position called?

The amplitude of a particle executing SHM is 0.1 m. The acceleration of the particle at a distance of 0.03 m from the equilibrium position is 0.12m*s^(-2) . What will be its velocity at a distance of 0.08 m from the position of equilibrium?

Time period and amplitude of a particle executing SHM are 2 s and 5 cm respectively. Determine its velocity and acceleration at a distacne of 3 cm from the equilibrium position.

The maximum acceleration of a particle executing simple harmonic motion is 0.296m*s^(-2) , its time period is 2s and the displacement from the equilibrium position at the beginning of its motion is 0.015m. Determine the equation of motion of the particle.

Time period of a particle executing SHM is T = 1 second and its amplitude of vibration is A = 0.04 m. Determine the maximum velocity and maximum acceleration of the particle.