The position time relation of a moving particle is x = `2t - 3t^2`What is the maximum (+) ve velocity of the particle?

The position-time relation of a moving particle is x = 2t -3t^(2) . What is the maximum positive velocity of the particle?

The position time relation of a moving particle is x = 2t - 3t^2 When does the velocity of the particle become zero? (x is in metre and t is in second)

The position-time relation of a moving particle is x = 2t -3t^(2) . When does the velocity of the particle become zero? (x is in metre and t is in second)

The position-time relation of a moving, particle is x = 2t - 3t^2 :- When does the velocity of the particle become zero? (x is in metre and t is in second)

The distance-time graph of a moving particle is given by x = 4t -6t^(2) . What is the positive maximum speed?

The distance-time graph of a moving particle is given by x = 4t -6t^(2) . At what time would the speed of the particle be zero ? ( x is in metre and t is in second).

Relation between distance covered s and time t of a moving particles is , s = 2t^(3)-4t^(2)+3t , What will be the velocity and acceleration after 3 s?

A particle starting from a point A and moving with a positive constant acceleration along a straight line reaches another point B is time T. Suppose that the initial velocity of the particle is u gt0 and P is the midpoint of the line AB. If the velocity of the particle at point P is v_(1) and if the velocity at time (T)/(2) is v_(2) , then -