The position time relation of a moving particle is x = `2t - 3t^2`When does the velocity of the particle become zero? (x is in metre and t is in second)

The position time relation of a moving particle is x = 2t - 3t^2 What is the maximum (+) ve velocity of the particle?

The position-time relation of a moving, particle is x = 2t - 3t^2 :- What is the maximum (+) ve velocity of the particle?

The position-time relation of a moving particle is x = 2t -3t^(2) . What is the maximum positive velocity of the particle?

The distance-time graph of a moving particle is given by x = 4t -6t^(2) . At what time would the speed of the particle be zero ? ( x is in metre and t is in second).

The distance-time graph of a moving particle is given by x = 4t -6t^(2) . What is the positive maximum speed?

The relation between the time taken and the displacement of a moving body is s = 2t - 3t^(2) + 4t^(3) , where the unit of s is in metre and that of t is in second. Find out the displacement, velocity and acceleration of the body 2s after initiation of the journey.

If the displacement of a particle changes with time as sqrt(x)=t+3 , then the velocity of the particle will be proportional to

The displacement x of a particle moving in one dimension under the action of a constant force is related to time t by the equation t = sqrt(x+3) where x is in meters and t is in seconds. Finds the displacement (in metres ) of the particle when its velocity is zero.

The position coordinate of a moving particle is given by x = 6+18t +9 t^(2) (where x is in metre, t in seconds. What is its velocity and acceleration at t = 2 s.

Position vector of a particle is related to time t as vecr=(t^2-1)hati+2thatj . The locus of the particle on the x-y plane is