A planet is rotating round a heavy star along a circular path of radius R with time T. If the gravitational force of attraction between planet & star is proportional `R^(-5//2)` then `T^2 prop R^x` what is the value of x?

A planet is rotating round a heavy star along a circular path of radius R with time T. if the gravitational force of attraction between planet and star is proportional to R^(-5/2) , then T^2 prop R^x . What is the value of x ?

Imagine a light planet revolving around a very heavy star in a circular path. The radius of the orbit =R and the time period of revolution =T. if the gravitational force of attraction between the star and the planet is directly proportional to R^(-5//2) , then the relation between T and R would be T^2 prop R^n . Determine the value of n.

A particle in motion covers half of a circular path of radius r in time t . Find the average speed and average velocity of the body.

An artificial satellite is revolving around the earth in a circular orbit of radius r. If the time period of revolution of the satellite is T, show that T^2 prop r^3 .

If a planet of mass m revolves round sun of mass M_0 in the.circular path of radius r, then what will Be the velocity of resolution of that planet?

A particle is moving in a circular path of radius a under the action of an attraction potential U = - (k)/(2r^(2)) . Its total energy is

Angular momentum of a body of mass m rotating along a circular path of radius r with uniform speed is L. What is the magnitude of the centripetal force acting on it?

A body of mass m is rotated along a circular path of radius r with uniform speed v. Centripetal force acting on the body is (mv^(2))/(r ) . If the body travels through a semicircular path, then what will be the work done by the centripetal force?