There are three molecules A, B & C in a gaseous mixture, whose mass are — `m_A > m_B > m_c`. Arange in the order of r.m.s. velocity.

There are three molecules A, B & C in a gaseous mixture, whose mass are — m_A > m_B > m_c . Arange in the order of average kinetic energy.

Two ideal gases A and B have molar masses M_(A) and M_(B)g*mol^(-1) respectively. Volumes of the same mass of A and B are the same, and the rms velocity of A molecules is twice that of the molecules of B. if M_(A):M_(B)=2:1 , then the ratio of the pressures of A to B is-

The r.m.s speed of the molecules of a gas at 100^(@)C is v. The temperature at which the r.m.s speed will be sqrt3v is

Average velocity of the molecules of a gas is 400m*s^(-1) . At the same temperature, what will be rms velocity o the molecules?

For two gases A and B with molecular masses M_A and M_B , it is observed that at a certain temperature T_1 the mean velocity of A is equal to the root mean square velocity of B, thus the mean velocity of A can be made equal to the mean velocity of B if

R.M.S. velocity of a molecule is C at pressure P. If pressure is increased two times, then r.m.s. velocity becomes—

Prove that c_(rms)=sqrt((2E)/(M)) [E=total kinetic energy of the molecules of 1 mol of a gas, M=molar mass of the gas, c_(rms)= root mean square velocity of gas molecule].

The rms velocity of CO gas molecules at 27^(@)C is approximately 1000 m/s. for N_(2) molecules at 600 K the rms velocity approximately-

The rms velocity of CO gas molecules at 27^@C is approximately 1000 m/s. For N_2 molecules at 600 K the rms velocity is approximately