Thermal conductivity of any matter is `0.50 cal//sec.cm^@C`. convert it into `"watt"//m^@C`.

The thermal conductivity of aluminium is 0.5 cal s^-1cm^-1 "@_C^-1 .Express it in S.I. system.

Thermal capacity of a body of mass 10 g is "8 cal ".^(@)C^(-1) . The specific heat of the material of the body is

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S.cm^(-1) . Calculate the molar conductivity of the KCl solution.

1.56 xx 10 ^(5) J of heat is conducted through a 2 m^(2) wall of 12 cm thick in one hour. Temperature difference between the two sides of the wall is 20 ^(@) C The thermal conductivity of the material of the wall is (in W m^(-1) K^(-1))

The temperature gradient at the earths surfae is 32^@C//km , and earth has average thermal conductivity of 0.008 CGS unit. R = 6000 km (radius of earth). Then what will be the loss of heat from earths surface?

Water protects organisms from thermal shock due its high (a) Thermal conductivity (b) Latent heat (c) Dielectric constant (d) All the above

The water equivalent of a calorimeter is 10g and it contains 50 g of water at 15^(@)C . Some amount of ice, initially at -10^(@)C is dropped in it and half of the ice melts till equilibrium is reached. What was the initial amount of ice that was dropped (when specific heat of ice =0.5"cal"gm^(-1)""^(@)C^(-1) specific heat of water =1.0"cal"gm^(-1)""^(@)C^(-1) and laten heat of melting of ice =80"cal"gm^(-1) )?