An object is in S.H.M. along `xx` axis at x = 0.04 m. Its potential energy is 0.04 J & Kinetic energy is 0.5 J. Calculate its amplitude.

A particle of mass 0.2kg is executing SHM along x-axis with a frequency of 25/piHz . If its kinetic energy is 0.5 J at x = 0.04 m, then find its amplitude of vibration?

When a particle executing SHM is at a distance of 0.02 m from its mean position, then its kinetic energy is thrice its potential energy. Calculate the amplitude of motion of the particle.

The kinetic energy of an electron is 4.55x10^(-25)J calculate the wavelength.

A particle of mass m has momentum p. What is its kinetic energy ?

When a particle executing SHM is at a distance of 0.02 m from its position of equilibrium, then its kinetic energy is twice its potential energy. Calculate the distance from the position of equilibrium where its potential energy is twice its kinetic energy.

An object of mass 10 kg executes SHM. Its time period and amplitude are 2s and 10 m respectively. Find its kinetic energy when it is at a distance of (i) 2 m and (ii) 5 m respectively from its position of equilibrium. Justify the two different results for (i) and (ii).

Frequency of a photon is 1.2xx10^(15)Hz . Calculate its energy in J.

A bomb explodes into two fragment of masses 2.0 kg and 1.0kg. The total kinetic energy of the fragment is 3.0xx10^4J . Calculate (i) kinetic energy of the bigger fragment , (ii) momentum of the smaller fragment.