Prove that if earth is shrinked to be half of its radius then the length of a day will be of 6 hours.

Statement I : If earth shrinks ( without change in mass ) to half its present size length of the day would become 6 hours. Statement II : As size of earth changes its moment of inertia changes.

If the radius of the earth becomes half of the present radius , mass being constant, the weight of a body will be

If the radius of the earth becomes half of the present radius, mass being constant, the weight of a body will be

If the distance of the earth from the sun suddenly decreases to half its present value, then how many days will make a year ?

Prove that cyclic trapezium is isoscles trapezium and the length of its diagonals are same.

If the earth is assumed to be a sphere of radius R, the height above the surface of the earth where the value of the acceleration due to gravity will be half its value on the earth's surface is

At what height above the surface of the earth will the acceleration due to gravity be half of its value on the earth's surface ? Radius of the earth =6400 km.

If both the radius and the mean density of a planet are half the radius and the mean density of the earth, what will be the acceleration due to gravity on the surface of that planet ? Given that the acceleration due to gravity on the earth's surface =980 cm*s^(-2)