For the maximum range a body projected with intial velocity u is moving. What will be the kinetic energy at the maximum height of the body.

A body is moving with uniform velocity —

A body is projected with a velocity 20 m*s^(-1) , making an angle of 45^@ with the horizontal. Calculate the maximum height it can attain

The momentum of a body is numerically equal to the kinetic energy of the body. What is the velocity of the body ?

A body is projected with initial velocity u making an angle theta with the horizontal direction. Find the value of theta for which the horizontal range become maximum. Find the maximum range also.

A body is projected with initial velocity u making an angle theta with the horizontal direction . Find the value of theta for which the horizontal range becomes maximum . Find the maximum range also.

A body is projected vertically upwards with an initial velocity u_1 . Another is projected with initial velocity u_2 at an angle theta with the horizontal . If both of them reach the same height ,show that sin theta=(u_1)/(u_2) .

A body of mass 1kg , at a height of 8m above the ground , is thrown vertically upwards at a velocity of 250 cm*s^(-1) . What will be the kinetic energy of the body when it just reaches the ground ? ( g=980 cm*s^(-2))

A particle is projected with an initial velocity u, making an angle theta with the horizontal. Find the equation of the trajectory of the particle at any instant after the projection. Find expressions for the maximum height gained by the particle and its horizontal range.

The maximum range of a projectile is 2/sqrt3 times its actual range. What is the angle of projection for the actual range?

A moving body of mass 10 kg has 20 joules of kinetic energy. Calculate the speed of the body.