Velocity of two objets of mass 10 kg and 2 kg is `(2hati-7hatj+3hatk) m//s` and `(-10hati+35hatj-3hatk) m//s` respectively. Calculate the velocity of their centre of mass.

Two objects of mass 10 kg and 2kg are moving with velocities (2hati-7hatj+3hatk) m//s and (-10hati+35hatj-3hatk) m/s respectively. Calculate the velocity of the centre of mass of the system.

Two particles of masses 3 kg and 2kg are located at (-6hati+4hatj-2hatk) and (2hati+5hatj+13hatk) respectively. Locate the position of centre of mass.

The position vector of two masses of 6 unit and 2 unit is (6hati-7hatj) & (2hati + 5hatj) respectively. Find out the position of their centre of mass.

In a system comprising of two particles of mass 2 kg and 5 kg, the positions of the two particles at t=0 are (4hati+3hatj) and (6hati-7hatj+7hatk) respectively and the velocities are (10hati-6hatk) and (3hati+6hatj) respectively. Deduce the velocity of the centre of mass and the position of the centre or mass at t=0 and t=4 s

Find |vecaxxvecb| , if veca=2hati+hatj+3hatkand vecb=3hati+5hatj-2hatk

If vecA= 5hati+6hatj+3hatk and vecB=6hati-2hatj-6hatk , then

Two objects of 3 kg & 1 kg have position vectors (-6hati + 4hatj-2hatk) & (2hati +5hatj+13hatk) . What is its centre of mass?

Find |vecaxxvecb| , if veca=2hati-7hatj+7hatk and vecb=3hati-2hatj+2hatk

If veca=hati-2hatj+3hatk and vecb=-2hati+hatj-2hatk , then the value of |veca xx vecb| is -

The position vectors of the points A, B, C and D are hati+3hatj-hatk, -hati-hatj+hatk, 2hati-3hatj+3hatk and -3hati+2hatj+hatk respectively. Then, the ratio of the moduli of the vectors vec(AB) and vec(CD) is -