Calculate the value of ‘g' at height ‘h' from the earth’s surface.

What is the condition for setting up an artificial satellite at a height h from the earth’s surface? (Radius of the earth = R, mass of the earth= M).

If the radius of the earth-shrinks by 2% and its mass remain same, then calculate the value of g on the earth's surface.

Assume that the earth is a uniform sphere of radius R. If the acceleration due to gravity at a height h above the earth's surface is g_1 and at the same depth below the surface of the earth is g_2(h lt R) , then show that, g_2=g_1(1-h/R)(1+h/R)^2 .

Between the earth and the moon, which one has a greater escape velocity ? Give reason. or, Is the value of the escape velocity from the earth's surface the same as that from the surface of the moon ?

Calculate the height from earth’s surface at which value of g is 1% than that of the earth surface.

A satellite is revolving in a circular orbit at a height h from the earth's surface (radius of earth R,h lt lt R ). The minimum increase in its orbital velocity required so that the satellite could escape from the earth's gravitational field , is close to :(Neglect the effect of atmosphere)

The acceleration due to gravity at a height above the earth's surface is ……..than that at the same depth below the surface of the earth. [Fill in the blanks]

A simple pendulum has a time period T_1 when on earth's surface.and T_2 when taken to a height R above the earth’s surface, where R is the radius of the earth. Find the ratio T_2//T_1 .

Discuss the variation of g (i) with the height above the earth's surface