At which point, velocity of the projectile’s trajectory will be lowest.

A particle is projected from . the ground at an angle theta with the horizontal with an initial speed of ‘u’. Find the time after which velocity vector, of the projectile is perpendicular to the initial velocity

Statement I: If a particle of mass m is connected to a light rod and whirled in a vertical circle of radius R, then to complete the circle, the minimum velocity of the particle at the lowest point is sqrt(5gR) . Statement II: Mechanical energy is conserved and for the minimum velocity at the lowest point, the velocity at the highest point will be zero.

Statement I: During the flight of a projectile, the horizontal component of its velocity remains uniform . Statement II: The vertical component of the velocity of a projectile becomes zero at the highest point of its path.

At which points of its path, the velocity of a particle executing SHM becomes zero?

Statement I: The initial velocity of projectile =(ahati+bhatj) . The horizontal range becomes maximum for a=b. Statement II: for the same magnitude of initial velocity , the horizontal range of a projectile becomes maximum for the angle 45^@ of projection.

Maximum height of a projectile is H an range of projection is R when the projectile is projected with the velocity u. Show that R^2 = 16H (u^2/(2g)-H) .

A projectile is fired from the surface of the earth with a velocity of 5m *s^(-1) and angle theta with the horizontal . Another projectile fired from another planet with a velocity of 3 m*s^(-1) at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in m*s^(-2) ) (given g=9.8 m*s^(-2) )

A projectile is launched from the ground and it returns to the ground level. The horizontal range of the projectile is R= 175 m . If the horizontal component of the projectile's velocity at any instant is 25 m *s^(-1) , then determine the time of flight of the projectile.

The initial velocity of a projectile is (hati+2hatj)m//s , where hati and hatj are unit vectors along the horizontal and vertical directions respectively. Find out the locus of the projectile , taking g=10 m//s^2 .