If F = force is applied on a body of mass m for time t then it acquires the velocity V and displacement x. Then show that----`t=(mv)/F` & `x=1/2(mv^2)/F`

A force F acts on a stationary body of mass m for a time t. Show that, the kinetic energy of the body iin that time =(F^2t^2)/(2m) .

If the force acting on a body at time t is F = at^(-1)+bt^(2) then find out the dimensions of a and b.

A mass m acquires a velocity v after covering a distance x, when a force F is applied on it for time t. show that, t = (mv)/(F) and x = (1)/(2) (mv^(2))/(F) .

A body of mass m , starting from rest , moves with constant acceleration . After a time T it attains a velocity V. Show that the work done by the body in time t=1/2 m (V^2)/(T^2)*t^2*

If f(x)=x/(2^(x)-1) , then show that f(-1) = 2.