If two arms of any triangle are given by two vectors `veca` and `vecb` , then show that the area of the triangle =` 1/2`I`veca xx vecb`I.

For any two vectors veca and vec b show that |vec a.vec b|le |vec a|.|vecb|

For two vectors vecA and vecB , |vecA+vecB| is always true when

If veca and vecb are two vectors, such that |veca xx vecb|=2 , then find the value of [veca vecb veca xx vecb] .

If veca , vecb , vecc are position vectors of the vertices A, B, C of a triangle ABC, show that the area of the triangle ABC is 1/2 ​ [ veca × vecb + vecb × vecc + vecc × veca ] . Also deduce the condition for collinearity of the points A, B and C.

For any two vectors vecaandvecb , we always have |veca+vecb|le|veca|+|vecb| .

If vecr.veca=vecr.vecb=vecr.vecc=1/2 for some non zero vector vecr and veca,vecb,vecc are non coplanar, then the area of the triangle whose vertices are A(veca),B(vecb) and C(vecc) is

For any two vectors vecaandvecb , we always have |veca*vecb|le|veca||vecb|

If veca and vecb are two vectors such that |veca|=2,|vecb|=3 and veca.vecb =4 , then find the value of |veca-vecb|

Are the magnitudes of the two vectors (vecA-vecB) and (vecB-vecA) the same ?