If the resultant of two equal vectors P is P then find out the angle between them.

What change takes place in the value of the resultant of two vectors when the angle between them is increased from 0 to 90^@ ?

The resultant of two forces P and Q is 5 sqrt(P^2+Q^2) when the angle between them is alpha . When the angle changes to (90^@-alpha) , the resultant becomes 3sqrt(P^2+Q^2) . Show that, tan alpha =1/3 .

Two forces in the ratio 1:2 act simultaneously on a particle. The resultant of these forces is three times the first force. The angle between them is

When will the magnitude of the resultant of two equal vectors be (i) sqrt(2) times and

When will the magnitude of the resultant of two equal vectors be (ii) sqrt(3) times the magnitude of each of them ?

The resultant of two vectors of magnitude 3 unit and 4 unit is 5 unit. The angle between these two vectors will be---

If the vectors 3 vec p+ vec q ;5p-3 vec qa n d2 vec p+ vec q ;4 vec p-2 vec q are pairs of mutually perpendicular vectors, then find the angle between vectors vec pa n d vec qdot