`y = A sin(omega t- kx) Cm` this equation find out the dimension of `omega`?

W = 1/2 kx^2 in this equation find out the dimension of k, where w = stored potential energy and x = eloxgation of the spring.

A wave y = a sin (omega t - kx) being superposed with another wave produces a node at x = 0. The equation of the second wave should be

Find all the roots of x^(3)-1=0 . Show that if omega is a complex root of this equation, the other complex root is omega^(2) and 1+omega+omega^(2)=0.

The equation x= A sin omega t gives the relation between the time t and the corresponding displacement x of a moving particle where A and omega are constant. Prove that the acceleration of the particle is proportional to its displacement and is directed opposite to it.

The wave progresses along the x-axis with time t. The instantaneous displacement from the mean position is given by y = a sin [(omegat-kx)+theta] . Then the dimensions are

Equations of two light waves are y_(1) = 4 sin omega t and y_(2) = 3 sin (omega t + (pi)/(2)) . What is the amplitude of the resultant wave as they superpose on each other?

Two simple harmonic motions are given by x_(1) = a sin omega t + a cos omega t and x_(2) = a sin omega t + (a)/(sqrt3) cos omega t The ratio of the amplitudes of first and second motion and the phase difference between them are respectively

Y=Asin (omegat - kx), t and x stand for time and distance respectively. Obtain the dimensional formula of omega and K. 20.96 m 17.33m