Home
Class 11
PHYSICS
The equation of transverse wave is —y = ...

The equation of transverse wave is —`y = y_0 sin 2pi (ft -x/lambda)`.If the maximum velocity is 4 times the velocity of the wave than—

A

`lambda= (pi y_0)/4`

B

`lambda=(pi y_0)/2`

C

`1lambda= pi y_0`

D

`lambda=2 pi y_0`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of progressive wave is y = A sin (kx - omega t) . What is the maximum velocity?

A longitudinal wave is represented by x= x_(0) sin 2pi(nt -x//lamda) . The maximum particle velocity will be four times the wave velocity if :

The equation of a progressive wave is y = A sin 2pi (pt - x//5) . What is the ratio of particle velocity and wave velocity?

The equation of the progressive wave is y = 5 sinpi//2(100t-x) cm. The frequeny of the wave is---

The equation of a progressive wave is y=4sin(4pi t-0.04x +pi//3) where x is in meter and The velocity of the wave is

The equation of a wave is represented by y = 10^-4 sin (100t-x/10) , the velocity of the wave will be

The equation of a stationary wave is y = 2 A sin k x cos omega t . Find the amplitudes, velocities and wavelengths of the two progressive waves, which on superposition produce this stationary wave .

If the equation of a progressive wave is— y = 2 sin 2pi (t/4 - x/12) then what will be the displacement at x = 3m & t = 2 sec?