Velocity of any object is `10 m//s`. Find out the .angle of projection for which its can cover the maximum horizontal distance.

Mass of an object is 10g. Find out its weight?

The velocity of a projectile is 15m/s .At what angle to the horizontal should it be projected so that it cover maximum horizontal distance?

Find the angle of projection of a projectile for which the horizontal range and the maximum height are equal.

A body is projected with initial velocity u making an angle theta with the horizontal direction . Find the value of theta for which the horizontal range becomes maximum . Find the maximum range also.

A body is projected with initial velocity u making an angle theta with the horizontal direction. Find the value of theta for which the horizontal range become maximum. Find the maximum range also.

A particle of mass m is projected with a velocity v, making an angle of 45^(@) with the horizontal. The magnitude of the angular momentum of the projectile about the point of projection, when it is at its maximum height h, is

The resultant velocity of a projectile at its highest point is sqrt(6/7) times that at half the maximum height. Show that the angle of projection with respect to the horizontal is 30^@ .

The equation of the trajectory of a projectile on a vertical plane is y= ax-bx^2 , where a and b are constants, and x and y respectively are the horizontal distances of the projectile from the point of projection. Find out the maximum height attained by the projectile, and the angle of projection with respect to the horizontal.

A body is projected horizontally from the top of a building of height h. Velocity of projection is u. Find the horizontal distance between the foot of the building and the ground where it will strike.