Home
Class 11
PHYSICS
The motion of a particle is given by the...

The motion of a particle is given by the equation `s = (3t^3 + 7t^2 + 14t + 8) m`. The value of acceleration of the particle at t = 1 sec is—

A

`10m//s^2`

B

`32m//s^2`

C

`23m//s^2`

D

`16m//s^2`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

The x and y coordiates of a particle at any time t are given by x = 7t + 14 t^(2) and y = 5t, where x and y are in metre and t is in second. The acceleration of the particle at t = 5 s is

The displacement of a particle in S.H.M. varies according to the relation x= 4 (cos pi t +sin pi t ) . The amplitude of the particle is

A particle moving in a stright line covers a distance of x cm in t seconds, where x = t^(3) + 6t^(2) - 15t + 18. Find the velocity and acceleration of the paricle at the end of 2 seconds. When does the particle stop ?

A particle moves in a circle of radius 1.0 cm at a speed given by v = 2.0 t, where v is in cm cdot s^(-1) and t in seconds. Find the radial acceleration of the particle at t = 1 s.

The velocity of a moving particle is given by v = 6 +18t + 9t^(2) (x in metre t in second ) what is its acceleration at t = 2 s?

The acceleration of a particle moving along a straight line is (6t^(2)-3t)cm//s^(2) , at time t seconds. If the velocity of the particel at time 2 seconds be 10cm/s, find its velocity at time t seconds.

The position of a particle is given by, vecr = (3.0t hati -2.0t^2 hatj + 4.0 hatk)m where t is in seconds and the coefficients have the proper units for r to be in metres. What is the magnitude and direction of velocity of the particle at t = 2.0 s ?