If range of projection of a particle is four times than the height acquired by itself when thrown from point of projection, on ground, calculate the angle of projection.

If the range of a projectile, projected from the surface of the earth is four times the maximum height attained, what is the angle of projection ?

Statement I: The horizontal range of a projectile is the same for angles 30 ^@ and 60^@ of projection. Statement II: The horizontal range of projectile is independent of the angle of projection.

What is the angle of projection for attaining maximum vertical height ?

Find the angle of projection of a projectile for which the horizontal range and the maximum height are equal.

The equation of the trajectory of a projectile on a vertical plane is y= ax-bx^2 , where a and b are constants, and x and y respectively are the horizontal distances of the projectile from the point of projection. Find out the maximum height attained by the projectile, and the angle of projection with respect to the horizontal.

If the horizontal range is 4 times of the maximum height then what is the angle of projection?

The maximum range of a projectile is 2/sqrt3 times its actual range. What is the angle of projection for the actual range?

Prove that when an object is projected from a particular point on ground in a particular angle, then the path of its projection is parabolic.

In case of a projectite , speed of the particle at the top most position is half of its initial speed . The angle of projection with horizontal plane is