If speed of a projectile at its maximum height is half of its initial speed, what is the angle of projection?

In case of a projectite , speed of the particle at the top most position is half of its initial speed . The angle of projection with horizontal plane is

If the range of a projectile, projected from the surface of the earth is four times the maximum height attained, what is the angle of projection ?

If the horizontal range is 4 times of the maximum height then what is the angle of projection?

The equation of the trajectory of a projectile on a vertical plane is y= ax-bx^2 , where a and b are constants, and x and y respectively are the horizontal distances of the projectile from the point of projection. Find out the maximum height attained by the projectile, and the angle of projection with respect to the horizontal.

The maximum range of a projectile is 2/sqrt3 times its actual range. What is the angle of projection for the actual range?

Determine the relation between the kinetic energy of a projectile at maximum height and at initial position for maximum range.

A particle is projected at an angle theta_0 = 60^@ with horizontal, after sqrt3 seconds the angle of velocity vector with the horizontal is reduce to half of its initial value, find the speed of projection ( g = 10 m//sec^2 ).