An object is thrown at a velocity `1//sqrt2th` of its escape velocity from ground fo vertically upward. Calculate the maximum height that object can obtained. Define gravitational potential energy.

An object is thrown vertically upward with a speed of 30 m. s^(-1) .The velocity of the object half a second before it reaches the maximum height is

A body of mass m thrown vertically upwards attains a maximum height h. At what height will its kinetic energy be 75% of its initial value?

A body is projected with a velocity 20 m*s^(-1) , making an angle of 45^@ with the horizontal. Calculate the maximum height it can attain

A body is projected vertically upwards from the surface of earth with a velocity equal to half of escape speed. What is the maximum height attained by the body ?

An object is thrown vertically upwards with an initial velocity of 40 "m.s"^(-1) . (i) How long will the object move upwards? (ii) What will be the maximum height attained? (iii) How much time will it taken to reach the ground ? (iv) When will the object be at a height of 25 m from the ground ? (v) What will be its velocity after 2 s? [ g= 9.8 "m.s"^(-2)] .

A body thrown vertically upwards from a point with a velocity v_(0) rises to a maximum height and then comes back to the point. Then

An object is projected vertically upwards with a velocity u from the surface of the earth. Show that the maximum height reached by the object is h=(u^2R)/(2gR-u^2) where R is the radius of the earth. Calculate escape velocity from it.

Statement I : A body is dropped from a height h and another body is thrown simultaneously from the ground with a velocity u in the vertically upward direction. The meet after a time of (h)/(u) . Statement II : For a body projected in the vertically upward direction the ascent in the last second is always 4.9 m, whatever be the velocity of projection.

A stone is thrown from the ground with a velocity of 14 m *s^(-1) , making an angle 60^@ with the horizontal. (i) What is the maximum height attained by the stone ?