The co-ordinates of a moving particle at time t are given by `x = ct^3` and `y = bt^3`. Find the speed of the particle.

The distance-time graph of a moving particle is given by x = 4t -6t^(2) . At what time would the speed of the particle be zero ? ( x is in metre and t is in second).

The x and y coordiates of a particle at any time t are given by x = 7t + 14 t^(2) and y = 5t, where x and y are in metre and t is in second. The acceleration of the particle at t = 5 s is

If position of a particle at instant t is given by x = t^(4) find acceleration of the particle.

A particle is travelling along a straight line OX. The distance x (in metres) of the particle from O at a time t is given by x=37+27t-t^(3) where t is time in seconds. The distance of the particle from O when it comes to rest is

The distance-time graph of a moving particle is given by x = 4t -6t^(2) . What is the positive maximum speed?

The position-time relation of a moving, particle is x = 2t - 3t^2 :- What is the maximum (+) ve velocity of the particle?

The position time relation of a moving particle is x = 2t - 3t^2 What is the maximum (+) ve velocity of the particle?