You have three resistors of values `2Omega,3Omega` and `5Omega`. How will you join them so that the total resistance is less than `2Omega`. Draw diagram and find the total resistance.

Given the resistance of 1Omega,2Omega,3Omega, how will you combine them to get an equivalent resistance of: 6Omega

Given the resistance of 1Omega,2Omega,3Omega, how will you combine them to get an equivalent resistance of: (11//5)Omega

Given the resistance of 1Omega,2Omega,3Omega, how will you combine them to get an equivalent resistance of: (11//3)Omega

Given the resistance of 1Omega,2Omega,3Omega, how will you combine them to get an equivalent resistance of: (6//11)Omega?

Three resistance of magnitudes 20Omega,30Omega and 40Omega are connected in series.(i) What is the equivalent resistance? (ii) IF the potential difference across the resistance 20Omega is 1V, calculate the potential differences across the other two resistances and also the total potential difference across the combination.

In which combination three resistance 5Omega,10Omega & 15Omega are connected to give equivalent resistance will be less than 5Omega ? In domestic wearing gadgets are connected in which combination and why?

A parallel combination of three resistances of 6 Omega, 12 Omega and 12 Omega is connected in series with an electric cell of emf 1.5 V and internal resistance 2 Omega . Find out the currents through the three resistances.

We deremine the value of the fourth resistance to be 8Omega with the help of a Wheatstone bridge with three known resistance 100Omega , 10Omega , 80 Omega respectively . If the emf of the cell and its internal resistanc be 2 v and 1.1Omega respectively , find the current passing through the cell .