Find the ratio of resistance of two wire having cross section double of one another and length equal to each other.

The length,radius and resistivity of two wires are each in the ratio 1:3. The resistance of the comparatively thin wire is 20 Omega . Determine the resistance of the other wire.

The resistivity of a wire if its length be doubled-

The diameter of a metallic sphere is 6 cm. It is melted and drawn into a long wire having a circular cross section of diameter as 0.2 cm . Find the length of the wire.

A conductor of resistance 20 Omega having uniform cross sectional area is bent in the form of a closed ring. A cell of emf 1.5 V and of negligible internal resistance is joined to the ring between two points dividing the circumference of the ring in the ratio 3:1 Find the currents flowing through the two parts of the ring .

The lengths radii and specific resistance of two conducting wires are each in the ratio of 1:3. If the resistance of the thinner wire is 10 Omega then the resistance of the other wire will be

Length,diameter and specific resistance of two wires of different materials are each in the ratio 2:1 .One of the wires has a resistance of 10 ohm. Find the resistance of the other wire.

Two wires are having length , resistivity and their radius in the ratio of 1:3 . Resistance of the thinner wire is 10 Omega , then the resistance of the other wire will be

Length diameter and specific resistance of two wires of different materials are each in the radio 2:1. One of the wires has a resistance of 10 ohm. Find the resistance of 10 ohm. Find the lresistance of the other wire.

How does the resistance of a conductor depend on its length and cross sectional area?

Resistance of a wire of circular cross-section is 2 Omega . If both the length and radius of cross-section of the wire be halved, then what will be the resistance of the wire ?