For all values of a and b, show that the circle (x - 2) (x - 2 + a) + (y + 3) (y +3 + b) = 36 bisectsthe circumference of the circle.`(x-2)^2 + (y + 3)^2 = 36.`

For all values of a and, b show that the circle (x-2)(x-2+a)+(y+3) (y+3+b)=0 bisects the circumference of the circle (x-2)^(2)+(y+3)^(2)=36 .

The circle (x-4)^(2) + (y-3)^(2) = 9 -

Which of the following points lies on the circumference of the circle (x-2)^(2) + (y+3)^(2) = 25 ?

The circle (x+2)^(2) + (y-3)^(2) = 4 touches -

If the circle x^2+y^2+6x+8y+a=0 bisects the circumference of the circle x^2 + y^2 + 2x - 6y - b = 0 then (a + b) is equal to

The locus of the centre of the circle which bisects the circumferences of the circles x^2 + y^2 = 4 & x^2 + y^2-2x + 6y + 1 =0 is :

(a) If x : y = 3 : 4 , then find the value of the ratio (2x + y) : ( 9x - 2y) . (b) If x : y = 5 : 4 , then find the value of the ratio (x^(2) + xy) : (x^(2) - xy) .

If the chord of contact of tangents from a point on the circle x^(2) + y^(2) = a^(2) to the circle x^(2)+ y^(2)= b^(2) touches the circle x^(2) + y^(2) = c^(2) , then a, b, c are in-

The coordinates of the centre of the circle 2x^(2)+2y^(2) + ax + by + c= 0 are (3, - 4), find a and b.

If" " x^(2) + y^(2) = 1, "show that, "(3x - 4x^(3))^(2) + (3y - 4y^(3))^(2) = 1.