If `(alpha^2,alpha)`lies inside the triangle bounded by the lines x-5y+6=0,x-3y+2=0and x-2y-3=0 then find the value of `alpha`

Find the values of alpha so that the point P(alpha^2,alpha) lies inside or on the triangle formed by the lines x-5y+6=0,x-3y+2=0a n dx-2y-3=0.

Detemine all values of alpha for which the point (alpha, alpha^(2)) lines inside the triangle formed by the lines 2x+3y-1=0, x+2y-3=0 and 5x-6y-=1

The orthocentre of the triangle formed by the lines x+y=1,2x+3y=6 and 4x-y+4=0 lies in

Statement 1: The value of alpha for which the point (alpha,alpha^2) lies inside the triangle formed by the lines x=0,x+y=2 and 3y=x is (0,1)dot Statement 2: The parabola y=x^2 meets the line x+y=2 at (1,1)dot (a) Both the statements are true, and Statement-1 is the correct explanation of Statement 2. (b)Both the statements are true, and Statement-1 is not the correct explanation of Statement 2. (c) Statement 1 is true and Statement 2 is false. (d) Statement 1 is false and Statement 2 is true.

The area (in square unit ) of the triangle bounded by the lines y=2 , x + y=0 and x-y =0 is-

If the point (a^2,a+1) lies in the angle between the lines 3x-y+1=0 and x+2y-5=0 containing the origin, then find the value of adot

The complete set of real values of 'a' such that the point lies triangle p(a, sin a) lies inside the triangle formed by the lines x-2y +2= 0; x+y=0 and x-y-pi=0

Find alpha if (alpha, alpha^2) lies inside the triangle having sides along the lines 2x+3y=1, x+2y-3=0, 6y=5x-1.

Find the angle between the straight lines : 2x+3y-6=0and3x-2y+11=0

Find the distance between the lines 5x -12y + 2 = 0 and -5x + 12y + 3 = 0