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A={0,1} find `AxxAxxA`

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If A = (0,1), find AxxA

If A = {1, 2, 3}, find AxxAxxA.

In each of the following cases state whether the given statement is true or false : If A={1,0,-1}, then the value of n(AxxAxxA)=9 .

If A = [(1,-1,1),(2,-1,0),(1,0,0)] find A^(2) and show that A^(2) = A^(-1) .

Let A = [(2,q),(0,1)] and A^(8) = [(x,yq),(0,1)], find x - y.

If [1 0 0 0 1 0 0 0 1][x y z]=[1-1 0] , find x ,\ y\ a n d\ z .

If PxxQ={(2,-1),(3,0),(2,1),(3,1),(2,0),(3,-1)} , find P and Q.

If A={:[(1,0),(-1,7)] and I={:[(1,0),(0,1)] , then find k so that A^(2)=8A+kI

If A={:[(2,0,1),(1,0,-1),(0,-1,1)]:}, find the matrix for the polynomial A^(2)-4A+3I.

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UNITED BOOK HOUSE-JADAVPUR VIDYAPITH-EXERCISE
  1. A={a,b,c}and B={1,2,3,4} .Find the total number of relation from A to ...

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  2. If AleBshow that A-B=phi

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  3. A={0,1} find AxxAxxA

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  4. 2f(x)+3f(-x)=15-4x then [f(1)+f(-1)]=?

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  5. f(x)=a+b sinx,has max value of 7 an min value 1.Find f(pi//6)=?

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  6. tan25^@=a prove that (tan155^@-tan115^@)/(1+tan155^@.tan115^@)=(1-a^2)...

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  7. Prove that tan70^(@)=2tan50^(@)+tan20^(@).

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  8. a=(1+i)/sqrt2then a^6+a^4+a^2+1=?

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  9. x(x-3)=4,has two roots alphaand betathen alpha^2+beta^2=?

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  10. Find the area of the triangle formed by the straight lin x cosalpha+ys...

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  11. Straight line px-qy=r intercept the coordinate axis at the point (a,0)...

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  12. A relation R defined on the set of natural no as follows R={(x,y),x+5y...

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  13. cos(beta-gamma)+cos(gamma-alpha)+cos(alpha-beta)=-3/2 show that cosalp...

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  14. sintheta+sinphi=a,costheta+cosphi=bshow that tan((theta-phi)/2)=+-sqrt...

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  15. If cos theta=(acosphi+b)/(a+bcosphi)(theta,phiacute angle)show that ta...

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  16. In a triangle ABC if a cos^2(C/2)+c cos^2(A/2)=((3b)/2)show that sides...

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  17. If w be a imaginary cube root of uniyt and a+b+c=0 then show that (a+b...

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  18. An equilateral triangle in the Argan plane has vertix as z1,z2and z3wh...

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  19. If the equation x^2+px+qr=0and x^2+qx+pr=0(p!=q,r!=0)has same root the...

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  20. Prove that ^nPr=^(n-1)Pr+r^(n-1)P(r-1)(notation used are in their usua...

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