The foci of the ellipse `x^2/25+y^2/9=1` coincide with a hyperbola. If e=2 for hyperbola, find the equation of hyperbola.

The foci of the ellipse (x^(2))/(25) + (y^(2))/(9) = 1 coincide with the hyperbola. It e = 2 for hyperbola, find the equation of the hyperbola.

The foci of the hyperbola 4x^2-9y^2=36 is

The foci of a hyperbola coincide with the foci of the ellipse x^2/25 +y^2/9 =1 . Find the equation of the hyperbola if its eccentricity is 2.

If a hyperbola passes through the foci of the ellipse (x^2)/(25)+(y^2)/(16)=1 . Its transverse and conjugate axes coincide respectively with the major and minor axes of the ellipse and if the product of eccentricities of hyperbola and ellipse is 1 then the equation of a. hyperbola is (x^2)/9-(y^2)/(16)=1 b. the equation of hyperbola is (x^2)/9-(y^2)/(25)=1 c. focus of hyperbola is (5, 0) d. focus of hyperbola is (5sqrt(3),0)

let the eccentricity of the hyperbola x^2/a^2-y^2/b^2=1 be reciprocal to that of the ellipse x^2+4y^2=4. if the hyperbola passes through a focus of the ellipse then: (a) the equation of the hyperbola is x^2/3-y^2/2=1 (b) a focus of the hyperbola is (2,0) (c) the eccentricity of the hyperbola is sqrt(5/3) (d) the equation of the hyperbola is x^2-3y^2=3

Find the foci of the ellipse 25(x+1)^2+9(y+2)^2=225.

If foci of the ellipse (x^(2))/(16) + (y^(2))/(b^(2)) = 1 coincide with the foci of the hyperbola (x^(2)/(144) - (y^(2))/(81)) = (1)/(25) , then the value of b^(2) is -

The eccentricity of the hyperbola x^2-y^2=4 is

If the foci of (x^2)/(a^2)-(y^2)/(b^2)=1 coincide with the foci of (x^2)/(25)+(y^2)/9=1 and the eccentricity of the hyperbola is 2, then

If the foci of the ellipse (x^2)/(16)+(y^2)/(b^2)=1 and the hyperbola (x^2)/(144)-(y^2)/(81)=1/(25) coincide, then find the value of b^2