If `g_2 < 0`, then mention the name of the distribution on the basis of Kurtosis.

If G_1 ,G_2 are geometric means , and A is the arithmetic mean between two positive no. then show that G_1^2/G_2+G_2^2/G_1=2A .

If G_1 , G_2 and G denotes GM of the first group, GM of the second group and GM of the composite group respectively and if G_1 < G_2 , show that G_1 < G < G_2 .

If K_1 and K_2 are the respective equilibrium constants for the two reactions (i) XeF_6(g)+H_2O(g)iffXeOF_4(g)+2HF(g) (ii) XeO_4(g)+XeF_6(g)iffXeOF_4(g)+XeO_3F_2(g) The equilibrium constant for the reaction XeO_4(g)+2HF(g)iffXeO_3F_2(g)+H_2O(g) will be

N_2(g) + 2O_2 (g) rarr 2NO_2 (g) + X kJ 2NO (g) + O_2(g) rarr 2NO_2 (g) + Y kJ the enthalpy of.formation of NO is

If G is the geometric mean of xa n dy then prove that 1/(G^2-x^2)+1/(G^2-y^2)=1/(G^2)

Given : N_2(g) + 3H_2(g) iff 2NH_3(g), K_1 N_2(g) + O_2(g) iff 2NO(g), K_2 H_2(g) + 1/2 O_2(g) iff H_2O(g), K_3 The equilibrium constant for, 2NH_3(g) + 5/2 O_2(g) iff 2NO(g) + 3H_2O(g) will be :

For the equilibrium N_2 (g) + O_2(g) = 2 NO (g)

For Hl(g)=1/2H_2(g)+1/2l_2(g) magnitude of K=8, then magnitude of equilibrium constant for H_2(g)+l_2(g)=2Hl(g) is

K_1 and K_2 are the respective equilibrium constants for the following two reactions : (i) N_2 (g) + O_2 (g) iff 2NO(g) (ii) 2NO(g) + O_2(g) iff 2NO_2(g) Then the equilibrium constant for the reaction N_2 (g) + 2O_2(g) iff 2NO_2(g) will be