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In acid rain , SO(2) accounts by ....

In acid rain , `SO_(2)` accounts by .

A

0.7

B

1

C

0.5

D

0.3

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To solve the question regarding the contribution of sulfur dioxide (SO₂) in acid rain, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Acid Rain**: - Acid rain refers to any form of precipitation (rain, snow, sleet, or hail) that has a lower pH than normal rainwater. This is primarily due to the presence of sulfur dioxide (SO₂) and nitrogen oxides (NOₓ) in the atmosphere. 2. **Identifying the Role of SO₂**: - Sulfur dioxide is a significant contributor to acid rain. When SO₂ is released into the atmosphere, it can react with water vapor, oxygen, and other chemicals to form sulfuric acid (H₂SO₄), which lowers the pH of rainwater. 3. **Analyzing the Options**: - The question provides four options regarding the percentage of SO₂ in acid rain, which are: - a) 0.7 - b) 0.5 - c) 0.3 - We need to determine which option correctly represents the proportion of SO₂ in acid rain. 4. **Determining the Correct Answer**: - According to the information provided, sulfur dioxide accounts for approximately 70% of the components that lead to acid rain. In decimal form, 70% is equivalent to 0.7. - Therefore, the correct answer is option a) 0.7. 5. **Final Answer**: - The answer to the question "In acid rain, SO₂ accounts by" is **0.7**.
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In atmosphere, SO_(2) and NO are oxidised to SO_(3) and NO_(2) , respectively,w hcih react with water to given H_(2)SO_(4) and HNO_(3) . The resultant solution is called acid rain. SO_(2) dissolves in water to form diprotic acid. SO_(2)(g) +H_(2)O(l) hArr HSO_(3)^(Theta) + H^(o+), K_(a_(1)) = 10^(-2) . HSO_(3)^(Theta) hArr SO_(3)^(2-) + H^(o+), K_(a_(2)) = 10^(-7) and for equilibrium, SO_(2)(aq) + H_(2)O (l) hArr SO_(3)^(2-)(aq) +2H^(o+)(aq) K_(a) = K_(a_(1)) xx K_(a_(2)) = 10^(-9) at 300K . Which of the following reagnets will given white precipitate with the aqueous solution of sulphurous acid?

In atmosphere, SO_(2) and NO are oxidised to SO_(3) and NO_(2) , respectively,w hcih react with water to given H_(2)SO_(4) and HNO_(3) . The resultant solution is called acid rain. SO_(2) dissolves in water to form diprotic acid. SO_(2)(g) +H_(2)O(l) hArr HSO_(3)^(Theta) + H^(o+), K_(a_(1)) = 10^(-2) . HSO_(3)^(Theta) hArr SO_(3)^(2-) + H^(o+), K_(a_(2)) = 10^(-7) and for equilibrium, SO_(2)(aq) + H_(2)O (l) hArr SO_(3)^(2-)(aq) +2H^(o+)(aq) K_(a) = K_(a_(1)) xx K_(a_(2)) = 10^(-9) at 300K . The pH of 0.01M aqueous solutioon of sodium sulphite (Na_(2)SO_(3))

Assertion (A): S reacts with SO_(3)^(2-) and forms S_(2)O_(3)^(2-) Reason (R) : S is electorn deficient and acts and acid and SO_(3)^(2-) is a base in terms of Lewis acid theroy.

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