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A force of 50 N acts on a body for 10 s....

A force of 50 N acts on a body for 10 s. What will be the change in momentum of the body ?

A

200 N.s

B

400 N.s

C

500 N.s

D

1000 N.s

Text Solution

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The correct Answer is:
To solve the problem, we need to find the change in momentum of a body when a force is applied. We can use the relationship between force, change in momentum, and time. ### Step-by-Step Solution: **Step 1: Understand the relationship between force and momentum.** The force acting on an object is equal to the rate of change of momentum. Mathematically, this can be expressed as: \[ F = \frac{\Delta p}{\Delta t} \] where \( F \) is the force, \( \Delta p \) is the change in momentum, and \( \Delta t \) is the time duration over which the force acts. **Step 2: Rearrange the formula to find change in momentum.** We can rearrange the equation to solve for the change in momentum: \[ \Delta p = F \cdot \Delta t \] **Step 3: Substitute the given values into the equation.** From the problem, we know: - Force \( F = 50 \, \text{N} \) - Time \( \Delta t = 10 \, \text{s} \) Now, substituting these values into the equation: \[ \Delta p = 50 \, \text{N} \cdot 10 \, \text{s} \] **Step 4: Calculate the change in momentum.** Calculating the above expression gives: \[ \Delta p = 500 \, \text{N} \cdot \text{s} \] Thus, the change in momentum of the body is: \[ \Delta p = 500 \, \text{kg m/s} \] ### Final Answer: The change in momentum of the body is **500 kg m/s**. ---

To solve the problem, we need to find the change in momentum of a body when a force is applied. We can use the relationship between force, change in momentum, and time. ### Step-by-Step Solution: **Step 1: Understand the relationship between force and momentum.** The force acting on an object is equal to the rate of change of momentum. Mathematically, this can be expressed as: \[ F = \frac{\Delta p}{\Delta t} \] where \( F \) is the force, \( \Delta p \) is the change in momentum, and \( \Delta t \) is the time duration over which the force acts. ...
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